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**Phase Angle / Phase Question - Simple Harmonic Motion**

## Homework Statement

If I were given a function of displacement for simple harmonic motion in the form of:

x = Acos([tex]\omega[/tex]t + [tex]\phi[/tex])

Would the phase angle, [tex]\phi[/tex], always be the same? Say if I derived the equations into forms for velocity and acceleration as well. The phase angle would not change.. is that correct?

Also, I am confused about what is the phase and what is the phase angle? My textbook lists the "phase angle" as [tex]\phi[/tex] and some other sources list "phase" as ([tex]\omega[/tex]t + [tex]\phi[/tex]). What's the difference between these??

## Homework Equations

x = Acos([tex]\omega[/tex]t + [tex]\phi[/tex])

v = -[tex]\omega[/tex]Acos([tex]\omega[/tex]t + [tex]\phi[/tex])

a = -[tex]\omega[/tex]

^{2}Acos([tex]\omega[/tex]t + [tex]\phi[/tex])

## The Attempt at a Solution

My belief is that it wouldn't change, but I want to be 100% sure.

Thanks for your clarification!

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